What is the inverse of \sqrt[3]{ln(2x-x^2)} ?

The inverse of \sqrt[3]{ln(2x-x^2)} is 1-sqrt(-e^{x^3)+1},sqrt(-e^{x^3)+1}+1

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inverse of \sqrt[3]{ln(2x-x^2)}

inverse

1 - - e^{x^{3}} + 1, - e^{x^{3}} + 1 + 1

Solution steps

Replace

x

with

y

Solve for

1 - - e^{x^{3}} + 1, - e^{x^{3}} + 1 + 1

f (x) = (x - 7) (x - 9)

f (x) = \frac{2 x + 5}{x + 1}

2 (3^{x}) + 1

f (x) = - 3 (x - 1)^{2}

f (x) = - 4 x - \frac{2}{3}

What is the inverse of \sqrt[3]{ln(2x-x^2)} ?
The inverse of \sqrt[3]{ln(2x-x^2)} is 1-sqrt(-e^{x^3)+1},sqrt(-e^{x^3)+1}+1