What is the inverse of \sqrt[3]{8x}+4 ?

The inverse of \sqrt[3]{8x}+4 is (x^3-12x^2+48x-64)/8

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of \sqrt[3]{8x}+4

inverse

\frac{x ^{3} - 12 x ^{2} + 48 x - 64}{8}

Solution steps

Replace

x

with

y

Solve for

\frac{x ^{3} - 12 x ^{2} + 48 x - 64}{8}

f (x) = (3 x - 1)^{5}

f (x) = \frac{2 x + 3}{x - 1} = 5

f (x) = 12 - 2 x^{3}

9^{x} + 2 \cdot 3^{x} + 3

e^{l n (k) + 1}

What is the inverse of \sqrt[3]{8x}+4 ?
The inverse of \sqrt[3]{8x}+4 is (x^3-12x^2+48x-64)/8