What is the inverse of y=log_{7}(x^4) ?

The inverse of y=log_{7}(x^4) is sqrt(7^{x/2)},-sqrt(7^{x/2)}

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inverse of y=log_{7}(x^4)

inverse

y = lo g_{7} (x^{4})

7^{\frac{x}{2}}, - 7^{\frac{x}{2}}

Solution steps

y = lo g_{7} (x^{4})

Replace

x

with

y

x = lo g_{7} (y^{4})

Solve for

y, x = lo g_{7} (y^{4})

7^{\frac{x}{2}}, - 7^{\frac{x}{2}}

f (x) = 16 + 6 x - 6

13

- 7

f (x) = \frac{x - 6}{x + 3}

f (x) = e^{3 - x^{2}}

What is the inverse of y=log_{7}(x^4) ?
The inverse of y=log_{7}(x^4) is sqrt(7^{x/2)},-sqrt(7^{x/2)}