What is the inverse of f(x)=9+sqrt(3x-3) ?

The inverse of f(x)=9+sqrt(3x-3) is (x^2-18x+84)/3

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inverse of f(x)=9+sqrt(3x-3)

inverse

f (x) = 9 + 3 x - 3

\frac{x ^{2} - 18 x + 84}{3}

Solution steps

y = 9 + 3 x - 3

Replace

x

with

y

x = 9 + 3 y - 3

Solve for

y, x = 9 + 3 y - 3

\frac{x ^{2} - 18 x + 84}{3}

f (x) = \frac{4 x + 2}{8 x - 5}

f (x) = 12 + 4 x - 4

f (x) = 3 x^{4} + 5

3 + 2 ln (x)

tan (0.5)

What is the inverse of f(x)=9+sqrt(3x-3) ?
The inverse of f(x)=9+sqrt(3x-3) is (x^2-18x+84)/3