What is the inverse of f(x)=log_{7}(x^4) ?

The inverse of f(x)=log_{7}(x^4) is sqrt(7^{x/2)},-sqrt(7^{x/2)}

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inverse of f(x)=log_{7}(x^4)

inverse

f (x) = lo g_{7} (x^{4})

7^{\frac{x}{2}}, - 7^{\frac{x}{2}}

Solution steps

y = lo g_{7} (x^{4})

Replace

x

with

y

x = lo g_{7} (y^{4})

Solve for

y, x = lo g_{7} (y^{4})

7^{\frac{x}{2}}, - 7^{\frac{x}{2}}

f (x) = 12 - 4 x

f (x) = 2 x^{2} + 8 x - 1

f (x) = \frac{3 x - 2}{5 - 2 x}

f (x) = x - x - 1

f (x) = \frac{( 2 x - 1 )}{x + 2}

What is the inverse of f(x)=log_{7}(x^4) ?
The inverse of f(x)=log_{7}(x^4) is sqrt(7^{x/2)},-sqrt(7^{x/2)}