What is the inverse of log_{5}(x)+log_{5}(7) ?

The inverse of log_{5}(x)+log_{5}(7) is 1/7*5^x

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inverse of log_{5}(x)+log_{5}(7)

inverse

lo g_{5} (x) + lo g_{5} (7)

\frac{1}{7} \cdot 5^{x}

Solution steps

y = lo g_{5} (x) + lo g_{5} (7)

Replace

x

with

y

x = lo g_{5} (y) + lo g_{5} (7)

Solve for

y, x = lo g_{5} (y) + lo g_{5} (7)

\frac{1}{7} \cdot 5^{x}

ln (\frac{e ^{x}}{e ^{x} - 1})

f (x) = \frac{1}{( 2 x ) - 3}

f (x) = 30 x + 400

f (x) = lo g_{10} (x + 3)

f (x) = 2 + ln (x - 1)

What is the inverse of log_{5}(x)+log_{5}(7) ?
The inverse of log_{5}(x)+log_{5}(7) is 1/7*5^x