What is the inverse of f(x)=log_{5}(x)+log_{5}(7) ?

The inverse of f(x)=log_{5}(x)+log_{5}(7) is 1/7*5^x

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inverse of f(x)=log_{5}(x)+log_{5}(7)

inverse

f (x) = lo g_{5} (x) + lo g_{5} (7)

\frac{1}{7} \cdot 5^{x}

Solution steps

y = lo g_{5} (x) + lo g_{5} (7)

Replace

x

with

y

x = lo g_{5} (y) + lo g_{5} (7)

Solve for

y, x = lo g_{5} (y) + lo g_{5} (7)

\frac{1}{7} \cdot 5^{x}

f (n) = \frac{3}{4} n - \frac{3}{2}

2 (x - 3)^{2} + 5

f (x) = 6 x^{2} - 66 x + 184

f (x) = 2^{x} + 1

f (x) = 1 + 2 x + 3 x^{2}

What is the inverse of f(x)=log_{5}(x)+log_{5}(7) ?
The inverse of f(x)=log_{5}(x)+log_{5}(7) is 1/7*5^x