What is the domain of f(x)=((x^2-1))/(x+1) ?

The domain of f(x)=((x^2-1))/(x+1) is x -1

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domain of f(x)=((x^2-1))/(x+1)

domain

f (x) = \frac{( x ^{2} - 1 )}{x + 1}

x < - 1 or x > - 1

Interval Notation

(- \infty, - 1) \cup (- 1, \infty)

Solution steps

Find undefined (singularity) points:

x = - 1

The function domain

x < - 1 or x > - 1

f (x) = \frac{6}{x} + 12

f (x) = \frac{1}{5} x^{3} - 3

f (x) = - 2 x

\frac{3 x ^{2}}{x ^{2} - 4}

- \frac{2}{7} cos (\frac{7}{6} x)

What is the domain of f(x)=((x^2-1))/(x+1) ?
The domain of f(x)=((x^2-1))/(x+1) is x<-1\lor x>-1