What is the inverse of (sqrt(4+x))/(1-x) ?

The inverse of (sqrt(4+x))/(1-x) is (2x^2+1+sqrt(20x^2+1))/(2x^2),(2x^2+1-sqrt(20x^2+1))/(2x^2)

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inverse of (sqrt(4+x))/(1-x)

inverse

\frac{4 + x}{1 - x}

\frac{2 x ^{2} + 1 + 20 x ^{2} + 1}{2 x ^{2}}, \frac{2 x ^{2} + 1 - 20 x ^{2} + 1}{2 x ^{2}}

Solution steps

y = \frac{4 + x}{1 - x}

Replace

x

with

y

x = \frac{4 + y}{1 - y}

Solve for

y, x = \frac{4 + y}{1 - y}

\frac{2 x ^{2} + 1 + 20 x ^{2} + 1}{2 x ^{2}}, \frac{2 x ^{2} + 1 - 20 x ^{2} + 1}{2 x ^{2}}

f (x) = e^{- 2 x}

g (x) = 12 - 2 x - \frac{3}{2}

f (x) = 5 + 2 sin (\frac{x - 1}{x + 1})

f (x) = 10 + 5 x - 5

f (x) = 2^{x - 1} - 2^{- x - 1}

What is the inverse of (sqrt(4+x))/(1-x) ?
The inverse of (sqrt(4+x))/(1-x) is (2x^2+1+sqrt(20x^2+1))/(2x^2),(2x^2+1-sqrt(20x^2+1))/(2x^2)