What is the inverse of f(x)=-(x+1)^2+7 ?

The inverse of f(x)=-(x+1)^2+7 is sqrt(-x+7)-1,-sqrt(-x+7)-1

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inverse of f(x)=-(x+1)^2+7

inverse

f (x) = - (x + 1)^{2} + 7

- x + 7 - 1, - - x + 7 - 1

Solution steps

y = - (x + 1)^{2} + 7

Replace

x

with

y

x = - (y + 1)^{2} + 7

Solve for

y, x = - (y + 1)^{2} + 7

- x + 7 - 1, - - x + 7 - 1

f (x) = (x + 2)^{3} + 2

f (x) = 4 x + 2 + 6

f (x) = 5 x + 25

f (x) = \frac{8 x - 1}{2}

f (x) = ln (- x + 2)

What is the inverse of f(x)=-(x+1)^2+7 ?
The inverse of f(x)=-(x+1)^2+7 is sqrt(-x+7)-1,-sqrt(-x+7)-1