What is the inverse of f(x)=e^{x^2-1} ?

The inverse of f(x)=e^{x^2-1} is sqrt(ln(x)+1),-sqrt(ln(x)+1)

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inverse of f(x)=e^{x^2-1}

inverse

f (x) = e^{x^{2} - 1}

ln (x) + 1, - ln (x) + 1

Solution steps

y = e^{x^{2} - 1}

Replace

x

with

y

x = e^{y^{2} - 1}

Solve for

y, x = e^{y^{2} - 1}

ln (x) + 1, - ln (x) + 1

f (x) = e^{x^{2} - 9}

f (x) = lo g_{3} (x + 1) - 2

f (x) = 4 y = 5 (x + 2)

f (x) = \frac{1}{3} (x - 4)

2 π x^{2} + 12 π x

What is the inverse of f(x)=e^{x^2-1} ?
The inverse of f(x)=e^{x^2-1} is sqrt(ln(x)+1),-sqrt(ln(x)+1)