What is the inverse of f(x)= 1/3 log_{10}(2x) ?

The inverse of f(x)= 1/3 log_{10}(2x) is 125^x*2^{3x-1}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of f(x)= 1/3 log_{10}(2x)

inverse

f (x) = \frac{1}{3} lo g_{10} (2 x)

12 5^{x} \cdot 2^{3 x - 1}

Solution steps

y = \frac{1}{3} lo g_{10} (2 x)

Replace

x

with

y

x = \frac{1}{3} lo g_{10} (2 y)

Solve for

y, x = \frac{1}{3} lo g_{10} (2 y)

12 5^{x} \cdot 2^{3 x - 1}

f (x) = \frac{- 12 - 7 x}{4}

f (x) = 2^{x - 1} + 2

y = \frac{x}{2} + 3

y = - \frac{2}{3} x + 1

100 - x

What is the inverse of f(x)= 1/3 log_{10}(2x) ?
The inverse of f(x)= 1/3 log_{10}(2x) is 125^x*2^{3x-1}