What is the inverse of f(x)=4-1/((x+1)^2) ?

The inverse of f(x)=4-1/((x+1)^2) is sqrt(-1/(x-4))-1,-sqrt(-1/(x-4))-1

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inverse of f(x)=4-1/((x+1)^2)

inverse

f (x) = 4 - \frac{1}{( x + 1 ) ^{2}}

- \frac{1}{x - 4} - 1, - - \frac{1}{x - 4} - 1

Solution steps

y = 4 - \frac{1}{( x + 1 ) ^{2}}

Replace

x

with

y

x = 4 - \frac{1}{( y + 1 ) ^{2}}

Solve for

y, x = 4 - \frac{1}{( y + 1 ) ^{2}}

- \frac{1}{x - 4} - 1, - - \frac{1}{x - 4} - 1

2 x^{2} - 12 x + 13

4 (x - 3)^{2} + 2

f (x) = (- 20 x + 13)^{2}

\frac{7}{x - 4}

f (x) = \frac{- 4 x}{5 x + 2}

What is the inverse of f(x)=4-1/((x+1)^2) ?
The inverse of f(x)=4-1/((x+1)^2) is sqrt(-1/(x-4))-1,-sqrt(-1/(x-4))-1