What is the inverse of f(x)= 1/3 x^4 ?

The inverse of f(x)= 1/3 x^4 is \sqrt[4]{3}\sqrt[4]{x},-\sqrt[4]{3}\sqrt[4]{x}

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inverse of f(x)= 1/3 x^4

inverse

f (x) = \frac{1}{3} x^{4}

43 4 x, - 43 4 x

Solution steps

y = \frac{1}{3} x^{4}

Replace

x

with

y

x = \frac{1}{3} y^{4}

Solve for

y, x = \frac{1}{3} y^{4}

43 4 x, - 43 4 x

\frac{x + 3}{x - 7}

f (x) = x^{2}, x > 0

y = \frac{1}{3} lo g_{10} (x - 1) + 4

f (x) = \frac{x}{3} + 4

\frac{1}{x ^{2} - 9 x + 14}

What is the inverse of f(x)= 1/3 x^4 ?
The inverse of f(x)= 1/3 x^4 is \sqrt[4]{3}\sqrt[4]{x},-\sqrt[4]{3}\sqrt[4]{x}