What is the inverse of (81x^4)/(16) ?

The inverse of (81x^4)/(16) is (2\sqrt[4]{x})/3 ,-(2\sqrt[4]{x})/3

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inverse of (81x^4)/(16)

inverse

\frac{81 x ^{4}}{16}

\frac{2 4 x}{3}, - \frac{2 4 x}{3}

Solution steps

y = \frac{81 x ^{4}}{16}

Replace

x

with

y

x = \frac{81 y ^{4}}{16}

Solve for

y, x = \frac{81 y ^{4}}{16}

\frac{2 4 x}{3}, - \frac{2 4 x}{3}

f (x) = x^{2} + 16 + 2 x

y = \frac{8}{4 - 2 x}

f (x) = \frac{2}{5} x + \frac{1}{3}

g (x) = arccos (x)

f (x) = 4 + 5 x

What is the inverse of (81x^4)/(16) ?
The inverse of (81x^4)/(16) is (2\sqrt[4]{x})/3 ,-(2\sqrt[4]{x})/3