What is the inverse of f(x)=\sqrt[3]{-6+1} ?

The inverse of f(x)=\sqrt[3]{-6+1} is None

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inverse of f(x)=\sqrt[3]{-6+1}

inverse

f (x) = 3 - 6 + 1

None

Solution steps

y = 3 - 6 + 1

Since the function is a constant function it has no inverse function

None

f (x) = 45 - 0.45 x

\frac{6 x - 7}{2 x - 2}

y = \frac{( x ^{5} - 2 )}{3}

f (x) = 1 - \frac{1}{0.15 \cdot 10}

f (x) = \frac{- 3 x + 1}{- 4 x + 2}

What is the inverse of f(x)=\sqrt[3]{-6+1} ?
The inverse of f(x)=\sqrt[3]{-6+1} is None