What is the inverse of f(x)=(x-6)^2,[6,infinity ] ?

The inverse of f(x)=(x-6)^2,[6,infinity ] is sqrt(x)+6,-sqrt(x)+6

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inverse of f(x)=(x-6)^2,[6,infinity ]

inverse

f (x) = (x - 6)^{2}, [6, \infty]

x + 6, - x + 6

Solution steps

y = (x - 6)^{2}

Replace

x

with

y

x = (y - 6)^{2}

Solve for

y, x = (y - 6)^{2}

x + 6, - x + 6

\frac{1}{x ^{2} - 1}

f (x) = 13 - 6 x^{3}

f (x) = \frac{1}{2} (\frac{1}{2})^{x}

\frac{7}{s ^{4}}

f (x) = x + 8, x \geq - 8

What is the inverse of f(x)=(x-6)^2,[6,infinity ] ?
The inverse of f(x)=(x-6)^2,[6,infinity ] is sqrt(x)+6,-sqrt(x)+6