What is the inverse of y=(sqrt(x))/(sqrt(x)-3) ?

The inverse of y=(sqrt(x))/(sqrt(x)-3) is (9x^2)/(x^2-2x+1)

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inverse of y=(sqrt(x))/(sqrt(x)-3)

inverse

y = \frac{x}{x - 3}

\frac{9 x ^{2}}{x ^{2} - 2 x + 1}

Solution steps

y = \frac{x}{x - 3}

Replace

x

with

y

x = \frac{y}{y - 3}

Solve for

y, x = \frac{y}{y - 3}

\frac{9 x ^{2}}{x ^{2} - 2 x + 1}

f (4) = \frac{8}{x - 3}

f (x) = \frac{17}{x ^{2} + 8 x + 17}

\frac{4 x}{5 - x}

f (x) = 4 π x^{2}

f (x) = 4 x^{2} + 10

What is the inverse of y=(sqrt(x))/(sqrt(x)-3) ?
The inverse of y=(sqrt(x))/(sqrt(x)-3) is (9x^2)/(x^2-2x+1)