What is the inverse of 4x^2-28x+16y-31=0 ?

The inverse of 4x^2-28x+16y-31=0 is -(-7+4sqrt(-x+5))/2 ,(4sqrt(-x+5)+7)/2

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inverse of 4x^2-28x+16y-31=0

inverse

4 x^{2} - 28 x + 16 y - 31 = 0

- \frac{- 7 + 4 - x + 5}{2}, \frac{4 - x + 5 + 7}{2}

Solution steps

y = \frac{- 4 x ^{2} + 28 x + 31}{16}

Replace

x

with

y

x = \frac{- 4 y ^{2} + 28 y + 31}{16}

Solve for

y, x = \frac{- 4 y ^{2} + 28 y + 31}{16}

- \frac{- 7 + 4 - x + 5}{2}, \frac{4 - x + 5 + 7}{2}

3 + x

- x^{2} - 1

f (x) = 7 + 5 x - 5

f (x) = 30 n + 400

f (x) = 12 - 2 x + \frac{3}{2}

What is the inverse of 4x^2-28x+16y-31=0 ?
The inverse of 4x^2-28x+16y-31=0 is -(-7+4sqrt(-x+5))/2 ,(4sqrt(-x+5)+7)/2