What is the inverse of f(x)=\sqrt[5]{x-2}-2 ?

The inverse of f(x)=\sqrt[5]{x-2}-2 is x^5+10x^4+40x^3+80x^2+80x+34

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of f(x)=\sqrt[5]{x-2}-2

inverse

f (x) = 5 x - 2 - 2

x^{5} + 10 x^{4} + 40 x^{3} + 80 x^{2} + 80 x + 34

Solution steps

y = 5 x - 2 - 2

Replace

x

with

y

x = 5 y - 2 - 2

Solve for

y, x = 5 y - 2 - 2

x^{5} + 10 x^{4} + 40 x^{3} + 80 x^{2} + 80 x + 34

\frac{5 x}{4 x - 5}

f (x) = - 5 (7) + 2

f (x) = 1.25 x + 61

y = lo g_{5} (x) + lo g_{5} (7)

f (x) = x^{2} - 9, x \geq 3

What is the inverse of f(x)=\sqrt[5]{x-2}-2 ?
The inverse of f(x)=\sqrt[5]{x-2}-2 is x^5+10x^4+40x^3+80x^2+80x+34