What is the parallel 4x+y-19=0,(6,3) ?

The parallel 4x+y-19=0,(6,3) is y=-4x+27

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parallel 4x+y-19=0,(6,3)

parallel

4 x + y - 19 = 0, (6, 3)

y = - 4 x + 27

Solution steps

Find the line

y = mx + b

parallel to

4 x + y - 19 = 0

that passes through

(6, 3)

Find the slope of

4 x + y - 19 = 0 : m = - 4

Compute the

y

intercept:

b = 27

Construct the line equation

y = mx + b

where

m = - 4

and

b = 27

y = - 4 x + 27

y = \frac{5 + x ^{4}}{x ^{2} - x ^{4}}

f (x) = - 16 t^{2} + 60 t + 2

f (x) = \frac{- 4 x}{5 + 3 x}

f (x) = \frac{( x + 17 )}{( x - 14 )}

f (x) = \frac{- 3 x - 2}{x + 3}