What is the inverse of f(x)=7x^2+4x-3 ?

The inverse of f(x)=7x^2+4x-3 is (-2+sqrt(7x+25))/7 ,-(sqrt(7x+25)+2)/7

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inverse of f(x)=7x^2+4x-3

inverse

f (x) = 7 x^{2} + 4 x - 3

\frac{- 2 + 7 x + 25}{7}, - \frac{7 x + 25 + 2}{7}

Solution steps

y = 7 x^{2} + 4 x - 3

Replace

x

with

y

x = 7 y^{2} + 4 y - 3

Solve for

y, x = 7 y^{2} + 4 y - 3

\frac{- 2 + 7 x + 25}{7}, - \frac{7 x + 25 + 2}{7}

5 x + 10

f (x) = 4 - \frac{2}{5} x

f (x) = - 13 x + 52

f (x) = \frac{x ^{2}}{x ^{2} - 9}

f (n) = - \frac{4}{n + 2} - 1

What is the inverse of f(x)=7x^2+4x-3 ?
The inverse of f(x)=7x^2+4x-3 is (-2+sqrt(7x+25))/7 ,-(sqrt(7x+25)+2)/7