What is the inverse of sqrt(log_{1/2)(x-3)} ?

The inverse of sqrt(log_{1/2)(x-3)} is (1/2)^{x^2}+3

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inverse of sqrt(log_{1/2)(x-3)}

inverse

lo g_{\frac{1}{2}} (x - 3)

(\frac{1}{2})^{x^{2}} + 3

Solution steps

y = lo g_{\frac{1}{2}} (x - 3)

Replace

x

with

y

x = lo g_{\frac{1}{2}} (y - 3)

Solve for

y, x = lo g_{\frac{1}{2}} (y - 3)

(\frac{1}{2})^{x^{2}} + 3

- 6 + 3 (16 - 1)

- x^{2} + 6 x - 7

f (x) = 1 0^{0.5 x}

3 (x + 4)^{2}

f (f) = f^{8}

What is the inverse of sqrt(log_{1/2)(x-3)} ?
The inverse of sqrt(log_{1/2)(x-3)} is (1/2)^{x^2}+3