What is the inverse of f(x)=f(x)=-3(x-1)^2+2 ?

The inverse of f(x)=f(x)=-3(x-1)^2+2 is sqrt(-(x-2)/3)+1,-sqrt(-(x-2)/3)+1

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inverse of f(x)=f(x)=-3(x-1)^2+2

inverse

f (x) = f (x) = - 3 (x - 1)^{2} + 2

- \frac{x - 2}{3} + 1, - - \frac{x - 2}{3} + 1

Solution steps

y = - 3 (x - 1)^{2} + 2

Replace

x

with

y

x = - 3 (y - 1)^{2} + 2

Solve for

y, x = - 3 (y - 1)^{2} + 2

- \frac{x - 2}{3} + 1, - - \frac{x - 2}{3} + 1

f (x) = \frac{3 t - 4}{t - 5}

y = \frac{e ^{x}}{e ^{x} + 1}

(x - 3) (x - 5)

f (x) = - x + 6 - 2

f (x) = - 3 - x^{3}

What is the inverse of f(x)=f(x)=-3(x-1)^2+2 ?
The inverse of f(x)=f(x)=-3(x-1)^2+2 is sqrt(-(x-2)/3)+1,-sqrt(-(x-2)/3)+1