What is the inverse of f(x)= 9/5 (x-273)+32 ?

The inverse of f(x)= 9/5 (x-273)+32 is (5x-160)/9+273

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of f(x)= 9/5 (x-273)+32

inverse

f (x) = \frac{9}{5} (x - 273) + 32

\frac{5 x - 160}{9} + 273

Solution steps

y = \frac{9}{5} (x - 273) + 32

Replace

x

with

y

x = \frac{9}{5} (y - 273) + 32

Solve for

y, x = \frac{9}{5} (y - 273) + 32

\frac{5 x - 160}{9} + 273

f (x) = 2 x - 2 - 2

\frac{x ^{2}}{x + 1}

2 x - 13

\frac{1}{x + 2} - 1

(2 x^{2} - 1) (- x^{2} - 6)

What is the inverse of f(x)= 9/5 (x-273)+32 ?
The inverse of f(x)= 9/5 (x-273)+32 is (5x-160)/9+273