What is the inverse of f(x)=4x^2-8x+1 ?

The inverse of f(x)=4x^2-8x+1 is (2+sqrt(x+3))/2 ,(2-sqrt(x+3))/2

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inverse of f(x)=4x^2-8x+1

inverse

f (x) = 4 x^{2} - 8 x + 1

\frac{2 + x + 3}{2}, \frac{2 - x + 3}{2}

Solution steps

y = 4 x^{2} - 8 x + 1

Replace

x

with

y

x = 4 y^{2} - 8 y + 1

Solve for

y, x = 4 y^{2} - 8 y + 1

\frac{2 + x + 3}{2}, \frac{2 - x + 3}{2}

f (x) = \frac{1}{x ^{3}} - 4

f (x) = - 9 - x

f (x) = \frac{23 - 3 x}{6 x}

f (x) = 1.4

y = - \frac{1}{2} 0 + \frac{4}{5}

What is the inverse of f(x)=4x^2-8x+1 ?
The inverse of f(x)=4x^2-8x+1 is (2+sqrt(x+3))/2 ,(2-sqrt(x+3))/2