What is the inverse of s/(s^2+4) ?

The inverse of s/(s^2+4) is (1+sqrt(1-16s^2))/(2s),(1-sqrt(1-16s^2))/(2s)

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inverse of s/(s^2+4)

inverse

\frac{s}{s ^{2} + 4}

\frac{1 + 1 - 16 s ^{2}}{2 s}, \frac{1 - 1 - 16 s ^{2}}{2 s}

Solution steps

y = \frac{s}{s ^{2} + 4}

Replace

s

with

y

s = \frac{y}{y ^{2} + 4}

Solve for

y, s = \frac{y}{y ^{2} + 4}

\frac{1 + 1 - 16 s ^{2}}{2 s}, \frac{1 - 1 - 16 s ^{2}}{2 s}

f (x) = 1 - \frac{2}{x ^{3}}

- sin (5 x)

y = ln (2 x + 1)

f (x) = 30 \cdot 1 7^{x}

f (x) = 13 - x^{2}

What is the inverse of s/(s^2+4) ?
The inverse of s/(s^2+4) is (1+sqrt(1-16s^2))/(2s),(1-sqrt(1-16s^2))/(2s)