What is the inverse of f(x)=4-(1-x/2)^2 ?

The inverse of f(x)=4-(1-x/2)^2 is -2sqrt(-x+4)+2,2sqrt(-x+4)+2

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inverse of f(x)=4-(1-x/2)^2

inverse

f (x) = 4 - (1 - \frac{x}{2})^{2}

- 2 - x + 4 + 2, 2 - x + 4 + 2

Solution steps

y = 4 - (1 - \frac{x}{2})^{2}

Replace

x

with

y

x = 4 - (1 - \frac{y}{2})^{2}

Solve for

y, x = 4 - (1 - \frac{y}{2})^{2}

- 2 - x + 4 + 2, 2 - x + 4 + 2

\frac{3}{s ^{2} + 4 s + 3}

2 x = ln (\frac{e ^{3 y} - 4}{3})

\frac{e ^{x} - 5}{4 - e ^{x}}

f (x) = x - 20

f (x) = x^{2} - 6 x + 2

What is the inverse of f(x)=4-(1-x/2)^2 ?
The inverse of f(x)=4-(1-x/2)^2 is -2sqrt(-x+4)+2,2sqrt(-x+4)+2