What is the inverse of sqrt(x-1)+sqrt(x+1) ?

The inverse of sqrt(x-1)+sqrt(x+1) is (x^4+4)/(4x^2)

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inverse of sqrt(x-1)+sqrt(x+1)

inverse

x - 1 + x + 1

\frac{x ^{4} + 4}{4 x ^{2}}

Solution steps

y = x - 1 + x + 1

Replace

x

with

y

x = y - 1 + y + 1

Solve for

y, x = y - 1 + y + 1

\frac{x ^{4} + 4}{4 x ^{2}}

2 (3 x + 1) + 4

f (x) = 1 + 3^{x}

f (x) = \frac{x + 4}{x + 12}

f (x) = \frac{x + 4}{x + 14}

y = \frac{x ^{2}}{x ^{2} + 1}

What is the inverse of sqrt(x-1)+sqrt(x+1) ?
The inverse of sqrt(x-1)+sqrt(x+1) is (x^4+4)/(4x^2)