What is the inverse of 2/(sqrt(x^3+27)) ?

The inverse of 2/(sqrt(x^3+27)) is cube root of (4-27x^2)/(x^2)

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inverse of 2/(sqrt(x^3+27))

inverse

\frac{2}{x ^{3} + 27}

3 \frac{4 - 27 x ^{2}}{x ^{2}}

Solution steps

y = \frac{2}{x ^{3} + 27}

Replace

x

with

y

x = \frac{2}{y ^{3} + 27}

Solve for

y, x = \frac{2}{y ^{3} + 27}

3 \frac{4 - 27 x ^{2}}{x ^{2}}

f (x) = \frac{( 2 x - 3 )}{3 x - 1}

f (x) = \frac{x}{6} + 8

3^{2}

y = 3 ln (x - 2)

f (x) = 50 - \frac{1}{3} x

What is the inverse of 2/(sqrt(x^3+27)) ?
The inverse of 2/(sqrt(x^3+27)) is cube root of (4-27x^2)/(x^2)