What is the inverse of y=2(x-4)^2-8 ?

The inverse of y=2(x-4)^2-8 is sqrt((x+8)/2)+4,-sqrt((x+8)/2)+4

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inverse of y=2(x-4)^2-8

inverse

y = 2 (x - 4)^{2} - 8

\frac{x + 8}{2} + 4, - \frac{x + 8}{2} + 4

Solution steps

y = 2 (x - 4)^{2} - 8

Replace

x

with

y

x = 2 (y - 4)^{2} - 8

Solve for

y, x = 2 (y - 4)^{2} - 8

\frac{x + 8}{2} + 4, - \frac{x + 8}{2} + 4

f (x) = 3 e^{2 x} - 1

f (x) = \frac{2 ^{x}}{3 + 2 ^{x}}

5 lo g_{e} (x - 10)

f (x) = \frac{8 x}{x - 2}

f (x) = \frac{5 x + 25}{9}

What is the inverse of y=2(x-4)^2-8 ?
The inverse of y=2(x-4)^2-8 is sqrt((x+8)/2)+4,-sqrt((x+8)/2)+4