What is the inverse of x^2+2x-1,x>0 ?

The inverse of x^2+2x-1,x>0 is -1+sqrt(x+2),-sqrt(x+2)-1

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inverse of x^2+2x-1,x>0

inverse

x^{2} + 2 x - 1, x > 0

- 1 + x + 2, - x + 2 - 1

Solution steps

y = x^{2} + 2 x - 1

Replace

x

with

y

x = y^{2} + 2 y - 1

Solve for

y, x = y^{2} + 2 y - 1

- 1 + x + 2, - x + 2 - 1

f (x) = 5 + x - 2

30 - 4 x - 2 x^{2}

f (x) = (\frac{x}{2}) - 3

y = 2 sin (x) + 1

\frac{4}{x + 2} - 5

What is the inverse of x^2+2x-1,x>0 ?
The inverse of x^2+2x-1,x>0 is -1+sqrt(x+2),-sqrt(x+2)-1