What is the inverse of f(x)=sqrt(x^3+1) ?

The inverse of f(x)=sqrt(x^3+1) is cube root of x^2-1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of f(x)=sqrt(x^3+1)

inverse

f (x) = x^{3} + 1

3 x^{2} - 1

Solution steps

y = x^{3} + 1

Replace

x

with

y

x = y^{3} + 1

Solve for

y, x = y^{3} + 1

3 x^{2} - 1

- 3 x - 5

f (x) = \frac{4}{x - 6}

f (x) = lo g_{\frac{1}{2}} (x - 3)

f (x) = \frac{9}{8 + x}

f (x) = arccos^{3} (\frac{3 x + 4}{x - 3})

What is the inverse of f(x)=sqrt(x^3+1) ?
The inverse of f(x)=sqrt(x^3+1) is cube root of x^2-1