What is the inverse of y=0.2log_{7}(3x+2)-9 ?

The inverse of y=0.2log_{7}(3x+2)-9 is (16807^{x+9}-2)/3

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inverse of y=0.2log_{7}(3x+2)-9

inverse

y = 0.2 lo g_{7} (3 x + 2) - 9

\frac{1680 7 ^{x + 9} - 2}{3}

Solution steps

y = 0.2 lo g_{7} (3 x + 2) - 9

Replace

x

with

y

x = 0.2 lo g_{7} (3 y + 2) - 9

Solve for

y, x = 0.2 lo g_{7} (3 y + 2) - 9

\frac{1680 7 ^{x + 9} - 2}{3}

f (x) = \frac{2}{x} - 6

(x - 7) (x - 9)

\frac{6 x - 1}{2 x + 7}

f (x) = f (x) = 2 x - 4

y = (x - 6)^{3}

What is the inverse of y=0.2log_{7}(3x+2)-9 ?
The inverse of y=0.2log_{7}(3x+2)-9 is (16807^{x+9}-2)/3