What is the inverse of y=log_{2}(x)-log_{2}(12) ?

The inverse of y=log_{2}(x)-log_{2}(12) is 3*2^{2+x}

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inverse of y=log_{2}(x)-log_{2}(12)

inverse

y = lo g_{2} (x) - lo g_{2} (12)

3 \cdot 2^{2 + x}

Solution steps

y = lo g_{2} (x) - lo g_{2} (12)

Replace

x

with

y

x = lo g_{2} (y) - lo g_{2} (12)

Solve for

y, x = lo g_{2} (y) - lo g_{2} (12)

3 \cdot 2^{2 + x}

f (x) = 14 - 2 x

y = \frac{3}{4} x + 2

4 x + 13

y = 3 + 2 - x

f (x) = \frac{3 - 9 x}{8 - 4 x}

What is the inverse of y=log_{2}(x)-log_{2}(12) ?
The inverse of y=log_{2}(x)-log_{2}(12) is 3*2^{2+x}