What is the inverse of-825/4 x^2+205x-67 ?

The inverse of-825/4 x^2+205x-67 is -(2(sqrt(-33x-530)-41))/(165),(2(sqrt(-33x-530)+41))/(165)

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inverse of-825/4 x^2+205x-67

inverse

- \frac{825}{4} x^{2} + 205 x - 67

- \frac{2 ( - 33 x - 530 - 41 )}{165}, \frac{2 ( - 33 x - 530 + 41 )}{165}

Solution steps

y = - \frac{825}{4} x^{2} + 205 x - 67

Replace

x

with

y

x = - \frac{825}{4} y^{2} + 205 y - 67

Solve for

y, x = - \frac{825}{4} y^{2} + 205 y - 67

- \frac{2 ( - 33 x - 530 - 41 )}{165}, \frac{2 ( - 33 x - 530 + 41 )}{165}

sin (6 (t - \frac{π}{6}))

f (x) = \frac{3}{4} x^{2} + 5 x - \frac{3}{5}

f (x) = 0.4 x + 2.5

ln (2 x + 3)

f (x) = \frac{x ^{2} + 1}{3}

What is the inverse of-825/4 x^2+205x-67 ?
The inverse of-825/4 x^2+205x-67 is -(2(sqrt(-33x-530)-41))/(165),(2(sqrt(-33x-530)+41))/(165)