What is the inverse of f(x)=(4-1)/((x+1)^2) ?

The inverse of f(x)=(4-1)/((x+1)^2) is sqrt(3/x)-1,-sqrt(3/x)-1

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inverse of f(x)=(4-1)/((x+1)^2)

inverse

f (x) = \frac{4 - 1}{( x + 1 ) ^{2}}

\frac{3}{x} - 1, - \frac{3}{x} - 1

Solution steps

y = \frac{4 - 1}{( x + 1 ) ^{2}}

Replace

x

with

y

x = \frac{4 - 1}{( y + 1 ) ^{2}}

Solve for

y, x = \frac{4 - 1}{( y + 1 ) ^{2}}

\frac{3}{x} - 1, - \frac{3}{x} - 1

f (x) = x (1 - x)

f (x) = \frac{2}{x - 3} - 2

f (x) = 1 + x + 2

3 x + 2 - 1

f (x) = 2 3 x - 3

What is the inverse of f(x)=(4-1)/((x+1)^2) ?
The inverse of f(x)=(4-1)/((x+1)^2) is sqrt(3/x)-1,-sqrt(3/x)-1