What is the inverse of f(x)=(x^2+2)/(x^2) ?

The inverse of f(x)=(x^2+2)/(x^2) is sqrt(2/(x-1)),-sqrt(2/(x-1))

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inverse of f(x)=(x^2+2)/(x^2)

inverse

f (x) = \frac{x ^{2} + 2}{x ^{2}}

\frac{2}{x - 1}, - \frac{2}{x - 1}

Solution steps

y = \frac{x ^{2} + 2}{x ^{2}}

Replace

x

with

y

x = \frac{y ^{2} + 2}{y ^{2}}

Solve for

y, x = \frac{y ^{2} + 2}{y ^{2}}

\frac{2}{x - 1}, - \frac{2}{x - 1}

f (x) = \frac{x - 2}{7}

e^{- y}

f (x) = \frac{2}{3 x + 3}

3 2 - x + 3

7 x

What is the inverse of f(x)=(x^2+2)/(x^2) ?
The inverse of f(x)=(x^2+2)/(x^2) is sqrt(2/(x-1)),-sqrt(2/(x-1))