What is the inverse of y= 2/(sqrt(1\frac{x^2){4)}} ?

The inverse of y= 2/(sqrt(1\frac{x^2){4)}} is 4/x ,-4/x

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inverse of y= 2/(sqrt(1\frac{x^2){4)}}

inverse

y = \frac{2}{1 \frac{x ^{2}}{4}}

\frac{4}{x}, - \frac{4}{x}

Solution steps

y = \frac{2}{1 \cdot \frac{x ^{2}}{4}}

Replace

x

with

y

x = \frac{2}{1 \cdot \frac{y ^{2}}{4}}

Solve for

y, x = \frac{2}{1 \frac{y ^{2}}{4}}

\frac{4}{x}, - \frac{4}{x}

\frac{x + 1}{x + 3}

ln (\frac{x - 1}{x + 1})

x^{10}

\frac{6 x ^{2} - 24}{2 x ^{2} - 4 x}

p^{0}

What is the inverse of y= 2/(sqrt(1\frac{x^2){4)}} ?
The inverse of y= 2/(sqrt(1\frac{x^2){4)}} is 4/x ,-4/x