What is the inverse of D/(Dx)(sqrt(x^2+8x)) ?

The inverse of D/(Dx)(sqrt(x^2+8x)) is -8/(1-x^2)

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inverse of D/(Dx)(sqrt(x^2+8x))

inverse

\frac{D}{D x} (x^{2} + 8 x)

- \frac{8}{1 - x ^{2}}

Solution steps

y = \frac{D}{D x} x^{2} + 8 x

Replace

x

with

y

x = \frac{D}{Dy} y^{2} + 8 y

Solve for

y, x = \frac{D}{Dy} y^{2} + 8 y

- \frac{8}{1 - x ^{2}}

e^{y^{2}}

\frac{x + 3}{x + 7}

f (x) = \frac{x ^{2}}{5}

f (x) = \frac{( 2 x + 1 )}{x - 2}

f (x) = \frac{4 x - 3}{7 x + 5}

What is the inverse of D/(Dx)(sqrt(x^2+8x)) ?
The inverse of D/(Dx)(sqrt(x^2+8x)) is -8/(1-x^2)