What is the inverse of f(x)=-2x^2+8x-7 ?

The inverse of f(x)=-2x^2+8x-7 is -(-8+sqrt(-8x+8))/4 ,-(-8-sqrt(-8x+8))/4

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inverse of f(x)=-2x^2+8x-7

inverse

f (x) = - 2 x^{2} + 8 x - 7

- \frac{- 8 + - 8 x + 8}{4}, - \frac{- 8 - - 8 x + 8}{4}

Solution steps

y = - 2 x^{2} + 8 x - 7

Replace

x

with

y

x = - 2 y^{2} + 8 y - 7

Solve for

y, x = - 2 y^{2} + 8 y - 7

- \frac{- 8 + - 8 x + 8}{4}, - \frac{- 8 - - 8 x + 8}{4}

y = (x + 1)^{2} + 2

4 - (\frac{1}{2})^{x + 2}

f (x) = 3 (x - 2)^{3} + 1

f (x) = \frac{x + 1}{2 x + 5}

[s + 41]

What is the inverse of f(x)=-2x^2+8x-7 ?
The inverse of f(x)=-2x^2+8x-7 is -(-8+sqrt(-8x+8))/4 ,-(-8-sqrt(-8x+8))/4