What is the inverse of f(x)=4+sqrt(3x-3) ?

The inverse of f(x)=4+sqrt(3x-3) is (x^2-8x+19)/3

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inverse of f(x)=4+sqrt(3x-3)

inverse

f (x) = 4 + 3 x - 3

\frac{x ^{2} - 8 x + 19}{3}

Solution steps

y = 4 + 3 x - 3

Replace

x

with

y

x = 4 + 3 y - 3

Solve for

y, x = 4 + 3 y - 3

\frac{x ^{2} - 8 x + 19}{3}

f (x) = \frac{3}{4} x + \frac{2}{7}

- 2^{x} + 3

f (x) = \frac{4 + x ^{2}}{3}

\frac{x ^{2}}{x ^{2} + 1}

f (x) = \frac{x}{( x + c )}

What is the inverse of f(x)=4+sqrt(3x-3) ?
The inverse of f(x)=4+sqrt(3x-3) is (x^2-8x+19)/3