What is the inverse of (x^2)/(x^2-4) ?

The inverse of (x^2)/(x^2-4) is (2sqrt(x)sqrt(x-1))/(x-1),-(2sqrt(x)sqrt(x-1))/(x-1)

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inverse of (x^2)/(x^2-4)

inverse

\frac{x ^{2}}{x ^{2} - 4}

\frac{2 x x - 1}{x - 1}, - \frac{2 x x - 1}{x - 1}

Solution steps

y = \frac{x ^{2}}{x ^{2} - 4}

Replace

x

with

y

x = \frac{y ^{2}}{y ^{2} - 4}

Solve for

y, x = \frac{y ^{2}}{y ^{2} - 4}

\frac{2 x x - 1}{x - 1}, - \frac{2 x x - 1}{x - 1}

f (x) = \frac{( 1 + 2 x )}{7 + x}

f (x) = x - 5 + 8

f (x) = \frac{e ^{x}}{7 + 4 e ^{x}}

f (x) = 13 x - 7

What is the inverse of (x^2)/(x^2-4) ?
The inverse of (x^2)/(x^2-4) is (2sqrt(x)sqrt(x-1))/(x-1),-(2sqrt(x)sqrt(x-1))/(x-1)