What is the inverse of f(x)=2x^2-4x+7 ?

The inverse of f(x)=2x^2-4x+7 is (4+sqrt(8x-40))/4 ,(4-sqrt(8x-40))/4

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inverse of f(x)=2x^2-4x+7

inverse

f (x) = 2 x^{2} - 4 x + 7

\frac{4 + 8 x - 40}{4}, \frac{4 - 8 x - 40}{4}

Solution steps

y = 2 x^{2} - 4 x + 7

Replace

x

with

y

x = 2 y^{2} - 4 y + 7

Solve for

y, x = 2 y^{2} - 4 y + 7

\frac{4 + 8 x - 40}{4}, \frac{4 - 8 x - 40}{4}

f (x) = 3 x^{\frac{1}{5}} - 4

f (x) = 4 x - 13

y = (x - 2)^{2} + 3

f (x) = 10 x + 14

f (x) = \frac{3}{2 - 7 x}

What is the inverse of f(x)=2x^2-4x+7 ?
The inverse of f(x)=2x^2-4x+7 is (4+sqrt(8x-40))/4 ,(4-sqrt(8x-40))/4