What is the inverse of f(x)=f(x)= 1/((2x)-3) ?

The inverse of f(x)=f(x)= 1/((2x)-3) is (1+3x)/(2x)

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inverse of f(x)=f(x)= 1/((2x)-3)

inverse

f (x) = f (x) = \frac{1}{( 2 x ) - 3}

\frac{1 + 3 x}{2 x}

Solution steps

y = \frac{1}{2 x - 3}

Replace

x

with

y

x = \frac{1}{2 y - 3}

Solve for

y, x = \frac{1}{2 y - 3}

\frac{1 + 3 x}{2 x}

f (x) = x, x \geq 0

1 - x^{3}

ln (2 - x) - ln (x - 1)

3 + \frac{2}{x}

f (x) = \frac{x + 5}{x + 10}

What is the inverse of f(x)=f(x)= 1/((2x)-3) ?
The inverse of f(x)=f(x)= 1/((2x)-3) is (1+3x)/(2x)