What is the inverse of f(x)=(2x-7)/(9x+1) ?

The inverse of f(x)=(2x-7)/(9x+1) is (-7-x)/(9x-2)

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inverse of f(x)=(2x-7)/(9x+1)

inverse

f (x) = \frac{2 x - 7}{9 x + 1}

\frac{- 7 - x}{9 x - 2}

Solution steps

y = \frac{2 x - 7}{9 x + 1}

Replace

x

with

y

x = \frac{2 y - 7}{9 y + 1}

Solve for

y, x = \frac{2 y - 7}{9 y + 1}

\frac{- 7 - x}{9 x - 2}

\frac{1}{s ^{2} + s + 1}

y = - lo g_{10} (x)

f (x) = \frac{2 x - 4}{x + \frac{3}{2}}

f (x) = - 1 - x

f (x) = 6 x^{2} + 66 x + 60

What is the inverse of f(x)=(2x-7)/(9x+1) ?
The inverse of f(x)=(2x-7)/(9x+1) is (-7-x)/(9x-2)