What is the inverse of f(x)=log_{2}(x-2)-1 ?

The inverse of f(x)=log_{2}(x-2)-1 is 2^{x+1}+2

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inverse of f(x)=log_{2}(x-2)-1

inverse

f (x) = lo g_{2} (x - 2) - 1

2^{x + 1} + 2

Solution steps

y = lo g_{2} (x - 2) - 1

Replace

x

with

y

x = lo g_{2} (y - 2) - 1

Solve for

y, x = lo g_{2} (y - 2) - 1

2^{x + 1} + 2

f (12) = x + x

7 - 3 x

f (x) = (x + 8) 2

4.7

f (x) = 12.8 - 4 x

What is the inverse of f(x)=log_{2}(x-2)-1 ?
The inverse of f(x)=log_{2}(x-2)-1 is 2^{x+1}+2