What is the inverse of f(x)= 1/(x^2-4) ?

The inverse of f(x)= 1/(x^2-4) is sqrt((1+4x)/x),-sqrt((1+4x)/x)

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inverse of f(x)= 1/(x^2-4)

inverse

f (x) = \frac{1}{x ^{2} - 4}

\frac{1 + 4 x}{x}, - \frac{1 + 4 x}{x}

Solution steps

y = \frac{1}{x ^{2} - 4}

Replace

x

with

y

x = \frac{1}{y ^{2} - 4}

Solve for

y, x = \frac{1}{y ^{2} - 4}

\frac{1 + 4 x}{x}, - \frac{1 + 4 x}{x}

f (x) = \frac{5 x}{x - 3}

y = 4 x - 9

f (x) = \frac{( 7 x + 3 )}{x - 5}

f (x) = 2 lo g_{9} (2 x - 5)

- \frac{31}{330} x^{2} - \frac{1007}{1650} x + 5.4

What is the inverse of f(x)= 1/(x^2-4) ?
The inverse of f(x)= 1/(x^2-4) is sqrt((1+4x)/x),-sqrt((1+4x)/x)