What is the inverse of sqrt((3x-1)/(2x+1)) ?

The inverse of sqrt((3x-1)/(2x+1)) is (-1-x^2)/(2x^2-3)

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inverse of sqrt((3x-1)/(2x+1))

inverse

\frac{3 x - 1}{2 x + 1}

\frac{- 1 - x ^{2}}{2 x ^{2} - 3}

Solution steps

y = \frac{3 x - 1}{2 x + 1}

Replace

x

with

y

x = \frac{3 y - 1}{2 y + 1}

Solve for

y, x = \frac{3 y - 1}{2 y + 1}

\frac{- 1 - x ^{2}}{2 x ^{2} - 3}

f (x) = ln (10 x + e)

f (x) = \frac{8 x + 1}{x - 7}

\frac{3 - 2 x}{x + 4}

2^{x - 3} - 5

x + 12

What is the inverse of sqrt((3x-1)/(2x+1)) ?
The inverse of sqrt((3x-1)/(2x+1)) is (-1-x^2)/(2x^2-3)