What is the inverse of f(x)=(x-19)^2 ?

The inverse of f(x)=(x-19)^2 is sqrt(x)+19,-sqrt(x)+19

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inverse of f(x)=(x-19)^2

inverse

f (x) = (x - 19)^{2}

x + 19, - x + 19

Solution steps

y = (x - 19)^{2}

Replace

x

with

y

x = (y - 19)^{2}

Solve for

y, x = (y - 19)^{2}

x + 19, - x + 19

f (x) = f (x) = - x^{2} + 4

\frac{x - 2}{2 x + 1}

tan (- \frac{3}{3})

f (x) = 4 (x + 8) - 9

f (x) = \frac{5 x - 15}{3 x + 7}

What is the inverse of f(x)=(x-19)^2 ?
The inverse of f(x)=(x-19)^2 is sqrt(x)+19,-sqrt(x)+19